1993 Romanian Open – Doubles

In the first edition of the tournament, Menno Oosting and Libor Pimek won the title by defeating George Cosac and Ciprian Petre Porumb 7–6, 7–6 in the final.[1]

Doubles
1993 Romanian Open
Final
ChampionsNetherlands Menno Oosting
Belgium Libor Pimek
Runners-upRomania George Cosac
Romania Ciprian Petre Porumb
Score7–6, 7–6
Details
Draw16 (1WC/1Q)
Seeds4
Events
Singles Doubles
Romanian Open · 1994 →

Seeds

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Draw

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Draw

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First round Quarterfinals Semifinals Final
1   M Oosting
  L Pimek
3 7 7
  C Brandi
  A Gaudenzi
6 5 5 1   M Oosting
  L Pimek
6 1 7
  J Ireland
  J Yancey
3 3   J Garat
  R Saad
4 6 6
  J Garat
  R Saad
6 6 1   M Oosting
  L Pimek
4 7 6
3   D Johnson
  K Kinnear
6 4 6 Q   T Krupa
  P Vízner
6 5 2
  Ģ Dzelde
  O Rahnasto
3 6 7   Ģ Dzelde
  O Rahnasto
2 6 1
Q   T Krupa
  P Vízner
7 3 6 Q   T Krupa
  P Vízner
6 4 6
  J Arrese
  F Roig
6 6 3 1   M Oosting
  L Pimek
7 7
  D Pescariu
  H Skoff
6 6 WC   G Cosac
  CP Porumb
6 6
  J Donar
  O Jonsson
4 4   D Pescariu
  H Skoff
6 2
WC   G Cosac
  CP Porumb
6 6 WC   G Cosac
  CP Porumb
7 6
4   R Båthman
  V Flégl
4 1 WC   G Cosac
  CP Porumb
3 6 7
  N Holm
  N Utgren
1 6 6   M Schapers
  D Vacek
6 3 6
  C Allgårdh
  T Nydahl
6 4 7   C Allgårdh
  T Nydahl
6 6 3
  M Schapers
  D Vacek
7 6   M Schapers
  D Vacek
7 4 6
2   M Bauer
  H de la Peña
6 4

References

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  1. ^ "Tennis 24: ATP Bucharest Doubles 1993 Results". Tennis 24. Retrieved 23 March 2023.
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