1824 United States presidential election in Maine

The 1824 United States presidential election in Maine took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for president and vice president.

1824 United States presidential election in Maine

← 1820 October 26 – December 2, 1824 1828 →
 
Nominee John Quincy Adams William H. Crawford
Party Democratic-Republican Democratic-Republican
Home state Massachusetts Georgia
Running mate John C. Calhoun Nathaniel Macon
Electoral vote 9 0
Popular vote 10,289 2,336
Percentage 81.50% 18.50%

County Results
Adams
  50–60%
  70–80%
  80–90%
  90–100%


President before election

James Monroe
Democratic-Republican

Elected President

John Quincy Adams
Democratic-Republican

During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the presidency. Maine voted for John Quincy Adams over William H. Crawford. Adams won Maine by a margin of 63.0%.

Results

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1824 United States presidential election in Maine[1]
Party Candidate Votes Percentage Electoral votes
Democratic-Republican John Quincy Adams 10,289 81.50% 9
Democratic-Republican William H. Crawford 2,336 18.50% 0
Totals 12,625 100.0% 9

See also

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Notes

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References

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  1. ^ "1824 Presidential General Election Results - Maine". U.S. Election Atlas. Retrieved February 27, 2013.