File:Punctured plane is not geodesically complete.svg

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English: The punctured plane is not geodesically complete because the maximal geodesic with initial conditions , does not have domain .
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Author Mathwriter2718

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The punctured plane \mathbb R^2 \backslash \{(0,0)\} is not geodesically complete because the maximal geodesic with initial conditions p = (1,1), v = (1,1) does not have domain \mathbb R.

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25 June 2024

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Date/TimeThumbnailDimensionsUserComment
current11:29, 27 June 2024Thumbnail for version as of 11:29, 27 June 2024190 × 189 (13 KB)Mathwriter2718Make it more consistent with the definition of "geodesically complete" given in the Riemannian geometry article
22:40, 25 June 2024Thumbnail for version as of 22:40, 25 June 2024190 × 189 (8 KB)Mathwriter2718Uploaded own work with UploadWizard
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